What element in Bohr form is 1s2 2s2 2p6 3s2 3p4?
The element you're looking for is sulfur, or
1s2 2s2 2p6 3s2 3p6 4s1
If you follow the configuration pattern, the electron configuration of ruthenium should be: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d6 5s2 or Kr 4d6 5s2. But the actual configuration of ruthenium is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d7 5s1 or Kr 4d7 5s1. I understand how the configuration.Show more. Source (s): electron configuration ruthenium ru: https://tr.im/ncFKi. Mar 01, 2021 In 3rd shell,we are getting 3s2 3p6. If I add all the valence electrons,we get 2 + 6 = 8 valence electrons in 1s2 2s2 2p6 3s2 3p6. From 1s2 2s2 2p6 3s2 3p6, we get totally 18 electrons.Among these 18 electrons, only 8 electrons are called valence electrons that are situated in the outermost shell (3s2 3p6).
Here's how you can use an element's electron configuration to determine its identity.
If you add all the electrons decribed in this electron configuration you'll get
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For a neutral atom, the number of electrons it has will match the number of protons in its nucleus, i.e. its atomic number. This means that the element you're looking for will have its atomic number equal to 16. According to the periodic table, this element is sulfur.
1s2 2s2 2p6 3s2 3p6 4s2 3d5
Read more on sulfur's Bohr model here: